What is the answer to x=sqrt((x-9)^2+21^2) ?

The answer to x=sqrt((x-9)^2+21^2) is x=29

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x=sqrt((x-9)^2+21^2)

x = (x - 9)^{2} + 2 1^{2}

x = 29

Solution steps

x = (x - 9)^{2} + 2 1^{2}

Square both sides:

x^{2} = x^{2} - 18 x + 522

x^{2} = x^{2} - 18 x + 522

Solve

x^{2} = x^{2} - 18 x + 522 : x = 29

x = 29

Verify Solutions:

x = 29

True

The solution is

x = 29

(10) = \frac{89}{x}

p - 3 p = 28

(v + 1)^{\frac{3}{2}} = 5

y^{2} = y^{\frac{1}{3}}

81 x = 18

What is the answer to x=sqrt((x-9)^2+21^2) ?
The answer to x=sqrt((x-9)^2+21^2) is x=29
Solve for x: x=sqrt((x-9)^2+21^2)
The solution is x=29