What is the answer to sqrt(4-x^2)=((4-x))/2 ?

The answer to sqrt(4-x^2)=((4-x))/2 is x= 8/5 ,x=0

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sqrt(4-x^2)=((4-x))/2

4 - x^{2} = \frac{( 4 - x )}{2}

x = \frac{8}{5}, x = 0

Decimal Notation

x = 1.6, x = 0

Solution steps

4 - x^{2} = \frac{( 4 - x )}{2}

Multiply both sides by

2

4 - x^{2} \cdot 2 = \frac{4 - x}{2} \cdot 2

Simplify

4 - x^{2} \cdot 2 = 4 - x

Square both sides:

16 - 4 x^{2} = 16 - 8 x + x^{2}

16 - 4 x^{2} = 16 - 8 x + x^{2}

Solve

16 - 4 x^{2} = 16 - 8 x + x^{2} : x = \frac{8}{5}, x = 0

x = \frac{8}{5}, x = 0

Verify Solutions:

x = \frac{8}{5}

True

, x = 0

True

The solutions are

x = \frac{8}{5}, x = 0

0.5 x - x^{0.5} = 0

2 x + 5 + 4 = 12

3 (x^{2} - 1) = x^{2} - 1

5 - x + 10 = 9, x

What is the answer to sqrt(4-x^2)=((4-x))/2 ?
The answer to sqrt(4-x^2)=((4-x))/2 is x= 8/5 ,x=0
Solve for x: sqrt(4-x^2)=((4-x))/2
The solution is x= 8/5 ,x=0