What is the answer to solvefor y,x=sqrt(4-y)+9 ?

The answer to solvefor y,x=sqrt(4-y)+9 is y=-x^2+18x-77 {x>= 9}

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solvefor y,x=sqrt(4-y)+9

solve for

y, x = 4 - y + 9

y = - x^{2} + 18 x - 77 {x \geq 9}

Solution steps

x = 4 - y + 9

Switch sides

4 - y + 9 = x

Move

9

to the right side

4 - y = x - 9

Square both sides:

4 - y = x^{2} - 18 x + 81

4 - y = x^{2} - 18 x + 81

Solve

4 - y = x^{2} - 18 x + 81 : y = - x^{2} + 18 x - 77

y = - x^{2} + 18 x - 77

Verify Solutions:

y = - x^{2} + 18 x - 77 {x \geq 9}

The solution is

y = - x^{2} + 18 x - 77 {x \geq 9}

y, x = 4 - y + 7

\frac{x}{4} = x

5 x + 1 = 10

12.25 = \frac{12.25 x ^{6.125}}{2}

What is the answer to solvefor y,x=sqrt(4-y)+9 ?
The answer to solvefor y,x=sqrt(4-y)+9 is y=-x^2+18x-77 {x>= 9}