What is (((4x^{-2})/(9x^2))^{(-1)/2})/(((8x^3){27y^3})^{\frac{-1)/3}} ?

The solution to (((4x^{-2})/(9x^2))^{(-1)/2})/(((8x^3){27y^3})^{\frac{-1)/3}} is (x^3)/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (((4x^{-2})/(9x^2))^{(-1)/2})/(((8x^3){27y^3})^{\frac{-1)/3}}

simplify

\frac{( \frac{4 x ^{- 2}}{9 x ^{2}} ) ^{\frac{- 1}{2}}}{( \frac{8 x ^{3}}{27 y ^{3}} ) ^{\frac{- 1}{3}}}

\frac{x ^{3}}{y}

Solution steps

\frac{( \frac{4 x ^{- 2}}{9 x ^{2}} ) ^{\frac{- 1}{2}}}{( \frac{8 x ^{3}}{27 y ^{3}} ) ^{\frac{- 1}{3}}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 1}{2} = - \frac{1}{2}

= \frac{( \frac{4 x ^{- 2}}{9 x ^{2}} ) ^{- \frac{1}{2}}}{( \frac{8 x ^{3}}{27 y ^{3}} ) ^{\frac{- 1}{3}}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 1}{3} = - \frac{1}{3}

= \frac{( \frac{4 x ^{- 2}}{9 x ^{2}} ) ^{- \frac{1}{2}}}{( \frac{8 x ^{3}}{27 y ^{3}} ) ^{- \frac{1}{3}}}

Simplify

(\frac{4 x ^{- 2}}{9 x ^{2}})^{- \frac{1}{2}} : \frac{3 x ^{2}}{2}

= \frac{\frac{3 x ^{2}}{2}}{( \frac{8 x ^{3}}{27 y ^{3}} ) ^{- \frac{1}{3}}}

Simplify

(\frac{8 x ^{3}}{27 y ^{3}})^{- \frac{1}{3}} : \frac{3 y}{2 x}

= \frac{\frac{3 x ^{2}}{2}}{\frac{3 y}{2 x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{3 x ^{2} \cdot 2 x}{2 \cdot 3 y}

Cancel

\frac{3 x ^{2} \cdot 2 x}{2 \cdot 3 y} : \frac{x ^{3}}{y}

= \frac{x ^{3}}{y}

10 \times \frac{38}{5}

32 + 3

8 x^{4} + 6 x^{6}

- 5.55 - 8.55 c + 4.35 c

- 5 \leq y < - 3

What is (((4x^{-2})/(9x^2))^{(-1)/2})/(((8x^3){27y^3})^{\frac{-1)/3}} ?
The solution to (((4x^{-2})/(9x^2))^{(-1)/2})/(((8x^3){27y^3})^{\frac{-1)/3}} is (x^3)/y