What is the answer to 13=sqrt((7-x)^2+(16-4)^2) ?

The answer to 13=sqrt((7-x)^2+(16-4)^2) is x=12,x=2

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13=sqrt((7-x)^2+(16-4)^2)

13 = (7 - x)^{2} + (16 - 4)^{2}

x = 12, x = 2

Solution steps

13 = (7 - x)^{2} + (16 - 4)^{2}

Square both sides:

169 = x^{2} - 14 x + 193

169 = x^{2} - 14 x + 193

Solve

169 = x^{2} - 14 x + 193 : x = 12, x = 2

x = 12, x = 2

Verify Solutions:

x = 12

True

, x = 2

True

The solutions are

x = 12, x = 2

- 7 + 25 - 4 x = - 2

x^{- 0.5} = \frac{1}{3}

- x^{2} + 3 x - 2 = 0

What is the answer to 13=sqrt((7-x)^2+(16-4)^2) ?
The answer to 13=sqrt((7-x)^2+(16-4)^2) is x=12,x=2
Solve for x: 13=sqrt((7-x)^2+(16-4)^2)
The solution is x=12,x=2