What are the solutions to the equation 25x^2+20x+4=0 ?

The solutions to the equation 25x^2+20x+4=0 are x=-2/5

Find the zeros of 25x^2+20x+4=0

The zeros of 25x^2+20x+4=0 are x=-2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} + 20 x + 4 = 0

x = - \frac{2}{5}

Solution steps

25 x^{2} + 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

2 0^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 25}

x = \frac{- 20}{2 \cdot 25}

\frac{- 20}{2 \cdot 25} = - \frac{2}{5}

x = - \frac{2}{5}

The solution to the quadratic equation is:

x = - \frac{2}{5}

12 = 6 y - 36

7 \cdot 3 - \frac{15}{5}

25 (2) + 40 (1) < 120

\frac{3}{\frac{2}{4}}

∣ - 2 v - 5 ∣ = 17

What are the solutions to the equation 25x^2+20x+4=0 ?
The solutions to the equation 25x^2+20x+4=0 are x=-2/5
Find the zeros of 25x^2+20x+4=0
The zeros of 25x^2+20x+4=0 are x=-2/5