What are the solutions to the equation 25x^2+20x+4=0 ?

The solutions to the equation 25x^2+20x+4=0 are x=-2/5

Find the zeros of 25x^2+20x+4=0

The zeros of 25x^2+20x+4=0 are x=-2/5

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25 x^{2} + 20 x + 4 = 0

x = - \frac{2}{5}

Decimal Notation

x = - 0.4

Solution steps

25 x^{2} + 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

2 0^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 25}

x = \frac{- 20}{2 \cdot 25}

\frac{- 20}{2 \cdot 25} = - \frac{2}{5}

x = - \frac{2}{5}

The solution to the quadratic equation is:

x = - \frac{2}{5}

12 = 6 y - 36

\frac{2.9}{2.9 - 3}

7 \cdot 3 - \frac{15}{5}

25 (2) + 40 (1) < 120

\frac{3}{\frac{2}{4}}

What are the solutions to the equation 25x^2+20x+4=0 ?
The solutions to the equation 25x^2+20x+4=0 are x=-2/5
Find the zeros of 25x^2+20x+4=0
The zeros of 25x^2+20x+4=0 are x=-2/5