What is the answer to |2x-1|=4-x^2 ?

The answer to |2x-1|=4-x^2 is x=-1\lor x=sqrt(6)-1

Solve for x: |2x-1|=4-x^2

The solution is x=-1\lor x=sqrt(6)-1

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∣ 2 x - 1 ∣ = 4 - x^{2}

x = - 1 or x = 6 - 1

Decimal Notation

x = - 1, x = 1.44948 \dots

Solution steps

∣ 2 x - 1 ∣ = 4 - x^{2}

Find positive and negative intervals

x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

x = - 1 or x = 6 - 1

15 = ∣ 12 - 4 c ∣

∣ - 4 c + 13 ∣ = 15

4 ∣ 2 y - 7 ∣ + 13 = 9

∣ 2 x - 3 ∣ + 5 = 10

\frac{a}{11} = 12

What is the answer to |2x-1|=4-x^2 ?
The answer to |2x-1|=4-x^2 is x=-1\lor x=sqrt(6)-1
Solve for x: |2x-1|=4-x^2
The solution is x=-1\lor x=sqrt(6)-1