What is the answer to |2x^2+1|=4x+7 ?

The answer to |2x^2+1|=4x+7 is x=-1\lor x=3

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|2x^2+1|=4x+7

2 x^{2} + 1 = 4 x + 7

x = - 1 or x = 3

Solution steps

2 x^{2} + 1 = 4 x + 7

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

(x = - 1 or x = 3)

x = - 1 or x = 3

8 = \frac{c}{12}

∣ 3 x + 14 ∣ = - 6 x

∣ x - 20 ∣ = 46

∣ x - 4 ∣ + 8 = 3 x

∣ 13 - 2 y ∣ = 19

What is the answer to |2x^2+1|=4x+7 ?
The answer to |2x^2+1|=4x+7 is x=-1\lor x=3
Solve for x: |2x^2+1|=4x+7
The solution is x=-1\lor x=3