What is factor a^4+ab^3-a^3b-b^4 ?

The solution to factor a^4+ab^3-a^3b-b^4 is (a+b)(a^2-ab+b^2)(a-b)

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factor a^4+ab^3-a^3b-b^4

factor

a^{4} + a b^{3} - a^{3} b - b^{4}

(a + b) (a^{2} - ab + b^{2}) (a - b)

Solution steps

a^{4} + a b^{3} - a^{3} b - b^{4}

= (a^{4} + a b^{3}) + (- a^{3} b - b^{4})

Factor out

a

from

a^{4} + a b^{3} : a (a^{3} + b^{3})

Factor out

- b

from

- a^{3} b - b^{4} : - b (a^{3} + b^{3})

= a (a^{3} + b^{3}) - b (a^{3} + b^{3})

Factor out common term

a^{3} + b^{3}

= (a^{3} + b^{3}) (a - b)

Factor

a^{3} + b^{3} : (a + b) (a^{2} - ab + b^{2})

= (a + b) (a^{2} - ab + b^{2}) (a - b)

17 \cdot 6

\frac{2 + i}{4 - i}

\frac{( 2 ^{2} + 2 ) - ( 6 ^{2} + 6 )}{2 - 6}

25 x^{2} - 16

\frac{3 x - 9}{4} = 7 x + 7

What is factor a^4+ab^3-a^3b-b^4 ?
The solution to factor a^4+ab^3-a^3b-b^4 is (a+b)(a^2-ab+b^2)(a-b)