What is the answer to |x^2+x-6|=x+1 ?

The answer to |x^2+x-6|=x+1 is x=sqrt(6)-1\lor x=sqrt(7)

Solve for x: |x^2+x-6|=x+1

The solution is x=sqrt(6)-1\lor x=sqrt(7)

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x^{2} + x - 6 = x + 1

x = 6 - 1 or x = 7

Decimal Notation

x = 1.44948 \dots, x = 2.64575 \dots

Solution steps

x^{2} + x - 6 = x + 1

Find positive and negative intervals

x \leq - 3, - 3 < x < 2, x \geq 2

Solve the inequality for each interval

No Solution or x = 6 - 1 or x = 7

x = 6 - 1 or x = 7

∣ 5 x + 7 ∣ - 9 = 3 x

∣ 2 x - 4 ∣ + 8 = x

2 ∣ 9 - 2 x ∣ - 9 = 1

x^{2} - 20 x - 1 = 20

∣ 6 w + 4 ∣ = 2 w - 10

What is the answer to |x^2+x-6|=x+1 ?
The answer to |x^2+x-6|=x+1 is x=sqrt(6)-1\lor x=sqrt(7)
Solve for x: |x^2+x-6|=x+1
The solution is x=sqrt(6)-1\lor x=sqrt(7)