What is the answer to |x^2-4x-5|=7 ?

The answer to |x^2-4x-5|=7 is x=-2\lor x=2-sqrt(2)\lor x=2+sqrt(2)\lor x=6

Solve for x: |x^2-4x-5|=7

The solution is x=-2\lor x=2-sqrt(2)\lor x=2+sqrt(2)\lor x=6

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x^{2} - 4 x - 5 = 7

x = - 2 or x = 2 - 2 or x = 2 + 2 or x = 6

Decimal Notation

x = - 2, x = 0.58578 \dots, x = 3.41421 \dots, x = 6

Solution steps

x^{2} - 4 x - 5 = 7

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x - 5 = - 7 or x^{2} - 4 x - 5 = 7

x^{2} - 4 x - 5 = - 7 or x^{2} - 4 x - 5 = 7

(x = 2 - 2 or x = 2 + 2) or (x = - 2 or x = 6)

x = - 2 or x = 2 - 2 or x = 2 + 2 or x = 6

x^{2} - 4 = x - 2

∣ 4 x + 3 ∣ - 4 = 3 x

30 = ∣ y + 10 ∣

∣ x - 7 ∣ = c

∣ v ∣ = 6

What is the answer to |x^2-4x-5|=7 ?
The answer to |x^2-4x-5|=7 is x=-2\lor x=2-sqrt(2)\lor x=2+sqrt(2)\lor x=6
Solve for x: |x^2-4x-5|=7
The solution is x=-2\lor x=2-sqrt(2)\lor x=2+sqrt(2)\lor x=6