What is (4x^2-1)/(4x^2+8x+3)<= 0 ?

The solution to (4x^2-1)/(4x^2+8x+3)<= 0 is -3/2 <x<-1/2 \lor-1/2 <x<= 1/2

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(4x^2-1)/(4x^2+8x+3)<= 0

\frac{4 x ^{2} - 1}{4 x ^{2} + 8 x + 3} \leq 0

- \frac{3}{2} < x < - \frac{1}{2} or - \frac{1}{2} < x \leq \frac{1}{2}

Interval Notation

(- \frac{3}{2}, - \frac{1}{2}) \cup (- \frac{1}{2}, \frac{1}{2}]

Decimal Notation

- 1.5 < x < - 0.5 or - 0.5 < x \leq 0.5

Solution steps

\frac{4 x ^{2} - 1}{4 x ^{2} + 8 x + 3} \leq 0

Factor

\frac{4 x ^{2} - 1}{4 x ^{2} + 8 x + 3} : \frac{( 2 x + 1 ) ( 2 x - 1 )}{( 2 x + 1 ) ( 2 x + 3 )}

\frac{( 2 x + 1 ) ( 2 x - 1 )}{( 2 x + 1 ) ( 2 x + 3 )} \leq 0

Identify the intervals

- \frac{3}{2} < x < - \frac{1}{2} or - \frac{1}{2} < x \leq \frac{1}{2}

\frac{5 x}{4 - 2 x} \geq \frac{1 + x}{x - 2}

(2 x^{4})^{3}

- 1 + \frac{5}{3}

300 = 113.31 t + 1.775 t^{2}

(\frac{5}{4}) (\frac{1}{2}) (- \frac{3}{2}) (- 3)

What is (4x^2-1)/(4x^2+8x+3)<= 0 ?
The solution to (4x^2-1)/(4x^2+8x+3)<= 0 is -3/2 <x<-1/2 \lor-1/2 <x<= 1/2