What is the answer to |x^2-x-4|=2 ?

The answer to |x^2-x-4|=2 is x=-2\lor x=-1\lor x=2\lor x=3

Solve for x: |x^2-x-4|=2

The solution is x=-2\lor x=-1\lor x=2\lor x=3

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x^{2} - x - 4 = 2

x = - 2 or x = - 1 or x = 2 or x = 3

Solution steps

x^{2} - x - 4 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - x - 4 = - 2 or x^{2} - x - 4 = 2

x^{2} - x - 4 = - 2 or x^{2} - x - 4 = 2

(x = - 1 or x = 2) or (x = - 2 or x = 3)

x = - 2 or x = - 1 or x = 2 or x = 3

5 ∣ 3 x - 4 ∣ = x + 1

∣ 4 x - 7 ∣ + 7 = 3 x

∣ 4 x - 1 ∣ = 7

∣ 6 x - 3 ∣ = 15

∣ 3 x - 1 ∣ + 8 + x = x + 4

What is the answer to |x^2-x-4|=2 ?
The answer to |x^2-x-4|=2 is x=-2\lor x=-1\lor x=2\lor x=3
Solve for x: |x^2-x-4|=2
The solution is x=-2\lor x=-1\lor x=2\lor x=3