What are the solutions to the equation solvefor y,x^2+2y^2=0 ?

The solutions to the equation solvefor y,x^2+2y^2=0 are y=i(sqrt(2)x)/2 ,y=-i(sqrt(2)x)/2

Find the zeros of solvefor y,x^2+2y^2=0

The zeros of solvefor y,x^2+2y^2=0 are y=i(sqrt(2)x)/2 ,y=-i(sqrt(2)x)/2

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solve for

y, x^{2} + 2 y^{2} = 0

y = i \frac{2 x}{2}, y = - i \frac{2 x}{2}

Solution steps

x^{2} + 2 y^{2} = 0

Move

x^{2}

to the right side

2 y^{2} = - x^{2}

Divide both sides by

2

y^{2} = - \frac{x ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{x ^{2}}{2}, y = - - \frac{x ^{2}}{2}

Simplify

- \frac{x ^{2}}{2} : i \frac{2 x}{2}

Simplify

- - \frac{x ^{2}}{2} : - i \frac{2 x}{2}

y = i \frac{2 x}{2}, y = - i \frac{2 x}{2}

9 w^{2} - 48 w v + 64 v^{2}

\frac{2}{3} + \frac{1}{2} - \frac{1}{3}

2 (- 2)^{3} + 3 (- 2)^{2} - 12 (- 2) + 6

\frac{1}{2} - \frac{m}{8} < \frac{7}{8}

8 a^{2} - 14 a - 15

What are the solutions to the equation solvefor y,x^2+2y^2=0 ?
The solutions to the equation solvefor y,x^2+2y^2=0 are y=i(sqrt(2)x)/2 ,y=-i(sqrt(2)x)/2
Find the zeros of solvefor y,x^2+2y^2=0
The zeros of solvefor y,x^2+2y^2=0 are y=i(sqrt(2)x)/2 ,y=-i(sqrt(2)x)/2