What is the answer to |x^2-x-1|=1 ?

The answer to |x^2-x-1|=1 is x=-1\lor x=0\lor x=1\lor x=2

Solve for x: |x^2-x-1|=1

The solution is x=-1\lor x=0\lor x=1\lor x=2

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x^{2} - x - 1 = 1

x = - 1 or x = 0 or x = 1 or x = 2

Solution steps

x^{2} - x - 1 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - x - 1 = - 1 or x^{2} - x - 1 = 1

x^{2} - x - 1 = - 1 or x^{2} - x - 1 = 1

(x = 0 or x = 1) or (x = - 1 or x = 2)

x = - 1 or x = 0 or x = 1 or x = 2

∣ 6 r - 9 ∣ = 27

∣ 3 - x ∣ + x = 4

∣ 3 x - 5 ∣ = x + 1

∣ k + 6 ∣ = 9

3 ∣ x - 6 ∣ = 16

What is the answer to |x^2-x-1|=1 ?
The answer to |x^2-x-1|=1 is x=-1\lor x=0\lor x=1\lor x=2
Solve for x: |x^2-x-1|=1
The solution is x=-1\lor x=0\lor x=1\lor x=2