What is the answer to |2x^2-3x+1|=1 ?

The answer to |2x^2-3x+1|=1 is x=0\lor x= 3/2

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|2x^2-3x+1|=1

2 x^{2} - 3 x + 1 = 1

x = 0 or x = \frac{3}{2}

Solution steps

2 x^{2} - 3 x + 1 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x^{2} - 3 x + 1 = - 1 or 2 x^{2} - 3 x + 1 = 1

2 x^{2} - 3 x + 1 = - 1 or 2 x^{2} - 3 x + 1 = 1

No Solution or (x = 0 or x = \frac{3}{2})

x = 0 or x = \frac{3}{2}

∣ 5 x + 15 ∣ = 5

∣ 6 n ∣ = 0

∣ 2 x + 5 ∣ + 2 = x

2 ∣ x + 1 ∣ - 3 = x - 2

2 ∣ k - 3 ∣ = 18

What is the answer to |2x^2-3x+1|=1 ?
The answer to |2x^2-3x+1|=1 is x=0\lor x= 3/2
Solve for x: |2x^2-3x+1|=1
The solution is x=0\lor x= 3/2