What are the solutions to the equation -2x^2+61x+330=12x ?

The solutions to the equation -2x^2+61x+330=12x are x=-11/2 ,x=30

Find the zeros of -2x^2+61x+330=12x

The zeros of -2x^2+61x+330=12x are x=-11/2 ,x=30

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- 2 x^{2} + 61 x + 330 = 12 x

x = - \frac{11}{2}, x = 30

Solution steps

- 2 x^{2} + 61 x + 330 = 12 x

Move

12 x

to the left side

- 2 x^{2} + 49 x + 330 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 ( - 2 ) \cdot 330}{2 ( - 2 )}

4 9^{2} - 4 (- 2) \cdot 330 = 71

x_{1, 2} = \frac{- 49 \pm 71}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 49 + 71}{2 ( - 2 )}, x_{2} = \frac{- 49 - 71}{2 ( - 2 )}

x = \frac{- 49 + 71}{2 ( - 2 )} : - \frac{11}{2}

x = \frac{- 49 - 71}{2 ( - 2 )} : 30

The solutions to the quadratic equation are:

x = - \frac{11}{2}, x = 30

2 x - 6 < 2

\frac{75}{10}

8 x^{2} - 72

(x - 2) (x + 7) \geq 0

\frac{1}{4} \cdot 5

What are the solutions to the equation -2x^2+61x+330=12x ?
The solutions to the equation -2x^2+61x+330=12x are x=-11/2 ,x=30
Find the zeros of -2x^2+61x+330=12x
The zeros of -2x^2+61x+330=12x are x=-11/2 ,x=30