What is the answer to |x^2-3x-1|=3 ?

The answer to |x^2-3x-1|=3 is x=-1\lor x=1\lor x=2\lor x=4

Solve for x: |x^2-3x-1|=3

The solution is x=-1\lor x=1\lor x=2\lor x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x - 1 = 3

x = - 1 or x = 1 or x = 2 or x = 4

Solution steps

x^{2} - 3 x - 1 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 3 x - 1 = - 3 or x^{2} - 3 x - 1 = 3

x^{2} - 3 x - 1 = - 3 or x^{2} - 3 x - 1 = 3

(x = 1 or x = 2) or (x = - 1 or x = 4)

x = - 1 or x = 1 or x = 2 or x = 4

∣ x + 1 ∣ = 3 x - 9

∣ x + 5 ∣ + 7 = 6

8 + 3 ∣ 4 x + 10 ∣ = 29

4 = 3 ∣ - 2 x ∣ + 4

- 4 ∣ 8 - 5 x ∣ = 13

What is the answer to |x^2-3x-1|=3 ?
The answer to |x^2-3x-1|=3 is x=-1\lor x=1\lor x=2\lor x=4
Solve for x: |x^2-3x-1|=3
The solution is x=-1\lor x=1\lor x=2\lor x=4