What is the answer to |0.5x+3|=x^2-4 ?

The answer to |0.5x+3|=x^2-4 is x=(1-sqrt(113))/4 \lor x=(1+sqrt(113))/4

Solve for x: |0.5x+3|=x^2-4

The solution is x=(1-sqrt(113))/4 \lor x=(1+sqrt(113))/4

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∣ 0.5 x + 3 ∣ = x^{2} - 4

x = \frac{1 - 113}{4} or x = \frac{1 + 113}{4}

Solution steps

∣ 0.5 x + 3 ∣ = x^{2} - 4

Find positive and negative intervals

x < - 6, x \geq - 6

Solve the inequality for each interval

No Solution or (x = \frac{1 - 113}{4} or x = \frac{1 + 113}{4})

x = \frac{1 - 113}{4} or x = \frac{1 + 113}{4}

∣ x + 4 ∣ = - 7

∣ x + 4 ∣ = 2 x

35 = ∣ x - 6 ∣

\frac{∣ - x - 6 ∣}{2} = 3

∣ 4 x + 4 ∣ + 6 = 46

What is the answer to |0.5x+3|=x^2-4 ?
The answer to |0.5x+3|=x^2-4 is x=(1-sqrt(113))/4 \lor x=(1+sqrt(113))/4
Solve for x: |0.5x+3|=x^2-4
The solution is x=(1-sqrt(113))/4 \lor x=(1+sqrt(113))/4