What is the answer to |x-2|=2-(x-2)^2 ?

The answer to |x-2|=2-(x-2)^2 is x=1\lor x=3

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|x-2|=2-(x-2)^2

∣ x - 2 ∣ = 2 - (x - 2)^{2}

x = 1 or x = 3

Solution steps

∣ x - 2 ∣ = 2 - (x - 2)^{2}

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

x = 1 or x = 3

3 + 4 ∣ x - 2 ∣ = 35

∣ 5 - x ∣ = 4

∣ 4 x + 9 ∣ - 6 = x

x, ∣ 5 x - 2 ∣ = 8

∣ 4 - 3 x ∣ = 10

What is the answer to |x-2|=2-(x-2)^2 ?
The answer to |x-2|=2-(x-2)^2 is x=1\lor x=3
Solve for x: |x-2|=2-(x-2)^2
The solution is x=1\lor x=3