What is the answer to |x-4|=x^2 ?

The answer to |x-4|=x^2 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

Solve for x: |x-4|=x^2

The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

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∣ x - 4 ∣ = x^{2}

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

Solution steps

∣ x - 4 ∣ = x^{2}

Find positive and negative intervals

x < 4, x \geq 4

Solve the inequality for each interval

(x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}) or No Solution

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

∣ t - 4 ∣ = 7 t + 12

∣ v ∣ = 3

∣ v ∣ = 5

x + 1 = x^{2} - 2 x - 3

2 ∣ x - 8 ∣ = 18

What is the answer to |x-4|=x^2 ?
The answer to |x-4|=x^2 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2
Solve for x: |x-4|=x^2
The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2