What are the solutions to the equation x^2-5x-12=0 ?

The solutions to the equation x^2-5x-12=0 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2

Find the zeros of x^2-5x-12=0

The zeros of x^2-5x-12=0 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2

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x^{2} - 5 x - 12 = 0

x = \frac{5 + 73}{2}, x = \frac{5 - 73}{2}

Solution steps

x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 12) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 1}

x = \frac{- ( - 5 ) + 73}{2 \cdot 1} : \frac{5 + 73}{2}

x = \frac{- ( - 5 ) - 73}{2 \cdot 1} : \frac{5 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{2}, x = \frac{5 - 73}{2}

x, f (a + h) = 3 x^{2} + 2 x

\frac{x ^{2} + 9 x + 20}{x + 1} > 0

\frac{x ^{5} y ^{4}}{x ^{- 5} y ^{4}}

(5 x - 1) (2 x + 1) - 10 x^{2} = 0.6

- 7 < 4 x - 3 < 4

What are the solutions to the equation x^2-5x-12=0 ?
The solutions to the equation x^2-5x-12=0 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2
Find the zeros of x^2-5x-12=0
The zeros of x^2-5x-12=0 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2