What are the solutions to the equation 4x^2-48x+144=0 ?

The solutions to the equation 4x^2-48x+144=0 are x=6

Find the zeros of 4x^2-48x+144=0

The zeros of 4x^2-48x+144=0 are x=6

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4 x^{2} - 48 x + 144 = 0

x = 6

Solution steps

4 x^{2} - 48 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 4 \cdot 144}{2 \cdot 4}

(- 48)^{2} - 4 \cdot 4 \cdot 144 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 48 )}{2 \cdot 4}

\frac{- ( - 48 )}{2 \cdot 4} = 6

x = 6

The solution to the quadratic equation is:

x = 6

4 (x + 1) = 2 (x + 5)

3 x < - 18.6

9 (9 - x) = 180

7^{2} + 1 0^{2} = x^{2}

(- \frac{5}{6})^{4}

What are the solutions to the equation 4x^2-48x+144=0 ?
The solutions to the equation 4x^2-48x+144=0 are x=6
Find the zeros of 4x^2-48x+144=0
The zeros of 4x^2-48x+144=0 are x=6