What is the answer to 3|6x+12|+12=40 ?

The answer to 3|6x+12|+12=40 is x=-32/9 \lor x=-4/9

Solve for x: 3|6x+12|+12=40

The solution is x=-32/9 \lor x=-4/9

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3 ∣ 6 x + 12 ∣ + 12 = 40

x = - \frac{32}{9} or x = - \frac{4}{9}

Decimal Notation

x = - 3.55555 \dots, x = - 0.44444 \dots

Solution steps

3 ∣ 6 x + 12 ∣ + 12 = 40

Move

12

to the right side

3 ∣ 6 x + 12 ∣ = 28

Divide both sides by

3

∣ 6 x + 12 ∣ = \frac{28}{3}

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

6 x + 12 = - \frac{28}{3} or 6 x + 12 = \frac{28}{3}

6 x + 12 = - \frac{28}{3} or 6 x + 12 = \frac{28}{3}

x = - \frac{32}{9} or x = - \frac{4}{9}

∣ x - 3 ∣ - 4 = 0

∣ 3 x - 2 ∣ = 16

∣ x + 7 ∣ - 3 = 15

∣ m ∣ = 4

∣ - 7 x ∣ = 49

What is the answer to 3|6x+12|+12=40 ?
The answer to 3|6x+12|+12=40 is x=-32/9 \lor x=-4/9
Solve for x: 3|6x+12|+12=40
The solution is x=-32/9 \lor x=-4/9