What are the solutions to the equation 7x^2+14=0 ?

The solutions to the equation 7x^2+14=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 7x^2+14=0

The zeros of 7x^2+14=0 are x=sqrt(2)i,x=-sqrt(2)i

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7 x^{2} + 14 = 0

x = 2 i, x = - 2 i

Solution steps

7 x^{2} + 14 = 0

Move

14

to the right side

7 x^{2} = - 14

Divide both sides by

7

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

x - 3 = - 14

4 x^{2} + 6 x - 10 = 0

- 15 + 3 x \geq 0

x (x + 7.5) > 38.5

- \frac{7}{15} x + 26 = \frac{1}{3} x + 2

What are the solutions to the equation 7x^2+14=0 ?
The solutions to the equation 7x^2+14=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 7x^2+14=0
The zeros of 7x^2+14=0 are x=sqrt(2)i,x=-sqrt(2)i