What is the answer to x^2-4|x|+2x-7=1 ?

The answer to x^2-4|x|+2x-7=1 is x=-3-sqrt(17)\lor x=4

Solve for x: x^2-4|x|+2x-7=1

The solution is x=-3-sqrt(17)\lor x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 ∣ x ∣ + 2 x - 7 = 1

x = - 3 - 17 or x = 4

Decimal Notation

x = - 7.12310 \dots, x = 4

Solution steps

x^{2} - 4 ∣ x ∣ + 2 x - 7 = 1

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = - 3 - 17 or x = 4

∣ 4 x - 5 ∣ = 2 x + 5

∣ 3 x - 5 ∣ = 8

40 - 4 x = 2 ∣ 3 x - 10 ∣

∣ 2 r + 5 ∣ = 4

∣ 8 x - 8 ∣ + 10 = - 14

What is the answer to x^2-4|x|+2x-7=1 ?
The answer to x^2-4|x|+2x-7=1 is x=-3-sqrt(17)\lor x=4
Solve for x: x^2-4|x|+2x-7=1
The solution is x=-3-sqrt(17)\lor x=4