What is the answer to ((4m-3))/7+((2m+5))/2 =3 ?

The answer to ((4m-3))/7+((2m+5))/2 =3 is m= 13/22

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((4m-3))/7+((2m+5))/2 =3

\frac{( 4 m - 3 )}{7} + \frac{( 2 m + 5 )}{2} = 3

m = \frac{13}{22}

Solution steps

\frac{( 4 m - 3 )}{7} + \frac{( 2 m + 5 )}{2} = 3

\frac{4 m - 3}{7} + \frac{2 m + 5}{2} = 3

Multiply by LCM

2 (4 m - 3) + 7 (2 m + 5) = 42

Expand

2 (4 m - 3) + 7 (2 m + 5) : 22 m + 29

22 m + 29 = 42

Move

29

to the right side

22 m = 13

Divide both sides by

22

m = \frac{13}{22}

\frac{1}{2} (7)

p - 3 = 3 p - 11

6 - 10

\frac{2 !}{1 ! \cdot 1 !}

\frac{4 a}{9} + 1 = \frac{5 a}{12}

What is the answer to ((4m-3))/7+((2m+5))/2 =3 ?
The answer to ((4m-3))/7+((2m+5))/2 =3 is m= 13/22
Solve for m: ((4m-3))/7+((2m+5))/2 =3
The solution is m= 13/22