What is the answer to |x(4-x)+4|=0 ?

The answer to |x(4-x)+4|=0 is x=-2(sqrt(2)-1)\lor x=2(1+sqrt(2))

Solve for x: |x(4-x)+4|=0

The solution is x=-2(sqrt(2)-1)\lor x=2(1+sqrt(2))

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∣ x (4 - x) + 4 ∣ = 0

x = - 2 (2 - 1) or x = 2 (1 + 2)

Decimal Notation

x = - 0.82842 \dots, x = 4.82842 \dots

Solution steps

∣ x (4 - x) + 4 ∣ = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x (4 - x) + 4 = 0

x (4 - x) + 4 = 0 : x = - 2 (2 - 1), x = 2 (1 + 2)

x = - 2 (2 - 1) or x = 2 (1 + 2)

∣ 4 x - 8 ∣ = 32

3 ∣ x + 5 ∣ - 2 = 7

∣ x + 2 ∣ = 3 x

2 ∣ x - 2 ∣ = 6

- 2 ∣ 2 x - 3 ∣ + 5 = - 9

What is the answer to |x(4-x)+4|=0 ?
The answer to |x(4-x)+4|=0 is x=-2(sqrt(2)-1)\lor x=2(1+sqrt(2))
Solve for x: |x(4-x)+4|=0
The solution is x=-2(sqrt(2)-1)\lor x=2(1+sqrt(2))