What are the solutions to the equation (3x-3)^2=4 ?

The solutions to the equation (3x-3)^2=4 are x= 5/3 ,x= 1/3

Find the zeros of (3x-3)^2=4

The zeros of (3x-3)^2=4 are x= 5/3 ,x= 1/3

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(3 x - 3)^{2} = 4

x = \frac{5}{3}, x = \frac{1}{3}

Solution steps

(3 x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 3 = 4 : x = \frac{5}{3}

Solve

3 x - 3 = - 4 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = \frac{1}{3}

5 [2 x - 4 (3 x + 1)] = - 10 x + 20

\frac{π}{6} + \frac{π}{3}

\frac{33}{2} = a^{2}

3 d^{2} + d - 10

4 z^{4} - 64 z^{2}

What are the solutions to the equation (3x-3)^2=4 ?
The solutions to the equation (3x-3)^2=4 are x= 5/3 ,x= 1/3
Find the zeros of (3x-3)^2=4
The zeros of (3x-3)^2=4 are x= 5/3 ,x= 1/3