What are the solutions to the equation 8x^2+4=-7x ?

The solutions to the equation 8x^2+4=-7x are x=-7/16+i(sqrt(79))/(16),x=-7/16-i(sqrt(79))/(16)

Find the zeros of 8x^2+4=-7x

The zeros of 8x^2+4=-7x are x=-7/16+i(sqrt(79))/(16),x=-7/16-i(sqrt(79))/(16)

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8 x^{2} + 4 = - 7 x

x = - \frac{7}{16} + i \frac{79}{16}, x = - \frac{7}{16} - i \frac{79}{16}

Solution steps

8 x^{2} + 4 = - 7 x

Move

7 x

to the left side

8 x^{2} + 4 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

Simplify

7^{2} - 4 \cdot 8 \cdot 4 : 79 i

x_{1, 2} = \frac{- 7 \pm 79 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 79 i}{2 \cdot 8}, x_{2} = \frac{- 7 - 79 i}{2 \cdot 8}

x = \frac{- 7 + 79 i}{2 \cdot 8} : - \frac{7}{16} + i \frac{79}{16}

x = \frac{- 7 - 79 i}{2 \cdot 8} : - \frac{7}{16} - i \frac{79}{16}

The solutions to the quadratic equation are:

x = - \frac{7}{16} + i \frac{79}{16}, x = - \frac{7}{16} - i \frac{79}{16}

∣ 2 (x - 1) + 8 ∣ \leq 18

4 x^{2} (x + 2) - 4 x (x + 2) + x + 2

\frac{5 x}{8} - 8 = \frac{2 x}{3}

x + 3 = 2 x + 8

5 + 2 + 9 + 4 + 8 = 122

What are the solutions to the equation 8x^2+4=-7x ?
The solutions to the equation 8x^2+4=-7x are x=-7/16+i(sqrt(79))/(16),x=-7/16-i(sqrt(79))/(16)
Find the zeros of 8x^2+4=-7x
The zeros of 8x^2+4=-7x are x=-7/16+i(sqrt(79))/(16),x=-7/16-i(sqrt(79))/(16)