What are the solutions to the equation x^2+45x+200=0 ?

The solutions to the equation x^2+45x+200=0 are x=-5,x=-40

Find the zeros of x^2+45x+200=0

The zeros of x^2+45x+200=0 are x=-5,x=-40

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x^{2} + 45 x + 200 = 0

x = - 5, x = - 40

Solution steps

x^{2} + 45 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

4 5^{2} - 4 \cdot 1 \cdot 200 = 35

x_{1, 2} = \frac{- 45 \pm 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 45 + 35}{2 \cdot 1}, x_{2} = \frac{- 45 - 35}{2 \cdot 1}

x = \frac{- 45 + 35}{2 \cdot 1} : - 5

x = \frac{- 45 - 35}{2 \cdot 1} : - 40

The solutions to the quadratic equation are:

x = - 5, x = - 40

1 > - 5 - a

\frac{n ^{2}}{( n + 1 ) ^{2}}

\frac{13 x ^{- 5} y ^{0}}{5 ^{- 3} z ^{- 10}}

f (3) x^{2} + 2 x

f - 8 \leq 10

What are the solutions to the equation x^2+45x+200=0 ?
The solutions to the equation x^2+45x+200=0 are x=-5,x=-40
Find the zeros of x^2+45x+200=0
The zeros of x^2+45x+200=0 are x=-5,x=-40