What is the answer to |2x^2-5x|=4-x ?

The answer to |2x^2-5x|=4-x is x=1-sqrt(3)\lor x=1\lor x=2\lor x=1+sqrt(3)

Solve for x: |2x^2-5x|=4-x

The solution is x=1-sqrt(3)\lor x=1\lor x=2\lor x=1+sqrt(3)

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2 x^{2} - 5 x = 4 - x

x = 1 - 3 or x = 1 or x = 2 or x = 1 + 3

Decimal Notation

x = - 0.73205 \dots, x = 1, x = 2, x = 2.73205 \dots

Solution steps

2 x^{2} - 5 x = 4 - x

Find positive and negative intervals

x \leq 0, 0 < x < \frac{5}{2}, x \geq \frac{5}{2}

Solve the inequality for each interval

x = 1 - 3 or (x = 1 or x = 2) or x = 1 + 3

x = 1 - 3 or x = 1 or x = 2 or x = 1 + 3

\frac{b}{3} = 2

∣ 3 - x ∣ = 0

2 ∣ 3 r - 9 ∣ - 1 = 23

∣ 2 t - 3 ∣ + 2 = 5

x^{2} + 4 x = 12

What is the answer to |2x^2-5x|=4-x ?
The answer to |2x^2-5x|=4-x is x=1-sqrt(3)\lor x=1\lor x=2\lor x=1+sqrt(3)
Solve for x: |2x^2-5x|=4-x
The solution is x=1-sqrt(3)\lor x=1\lor x=2\lor x=1+sqrt(3)