What is the answer to -6^0(n^0-4)-2(n-4)=-3(n+2^0) ?

The answer to -6^0(n^0-4)-2(n-4)=-3(n+2^0) is n=-14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-6^0(n^0-4)-2(n-4)=-3(n+2^0)

- 6^{0} (n^{0} - 4) - 2 (n - 4) = - 3 (n + 2^{0})

n = - 14

Solution steps

- 6^{0} (n^{0} - 4) - 2 (n - 4) = - 3 (n + 2^{0})

Simplify

- 6^{0} (n^{0} - 4) - 2 (n - 4) : 3 - 2 (n - 4)

3 - 2 (n - 4) = - 3 (n + 2^{0})

Expand

3 - 2 (n - 4) : - 2 n + 11

Expand

- 3 (n + 2^{0}) : - 3 n - 3

- 2 n + 11 = - 3 n - 3

Move

11

to the right side

- 2 n = - 3 n - 14

Move

3 n

to the left side

n = - 14

24 - 5 v = 8

(\frac{1}{4})^{\frac{- 1}{2}}

2 (x - 3) = 8

4 x + 5 > 8

- \frac{1}{3} \cdot (- \frac{4}{5})

What is the answer to -6^0(n^0-4)-2(n-4)=-3(n+2^0) ?
The answer to -6^0(n^0-4)-2(n-4)=-3(n+2^0) is n=-14
Solve for n: -6^0(n^0-4)-2(n-4)=-3(n+2^0)
The solution is n=-14