What is the answer to x^2-4|x-1|+5x+3=0 ?

The answer to x^2-4|x-1|+5x+3=0 is x=(-9-sqrt(85))/2 \lor x=(-9+sqrt(85))/2

Solve for x: x^2-4|x-1|+5x+3=0

The solution is x=(-9-sqrt(85))/2 \lor x=(-9+sqrt(85))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 ∣ x - 1 ∣ + 5 x + 3 = 0

x = \frac{- 9 - 85}{2} or x = \frac{- 9 + 85}{2}

Decimal Notation

x = - 9.10977 \dots, x = 0.10977 \dots

Solution steps

x^{2} - 4 ∣ x - 1 ∣ + 5 x + 3 = 0

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

(x = \frac{- 9 - 85}{2} or x = \frac{- 9 + 85}{2}) or No Solution

x = \frac{- 9 - 85}{2} or x = \frac{- 9 + 85}{2}

2 ∣ x - 1 ∣ = 14

2 ∣ x + 5 ∣ - 10 = 0

∣ u ∣ = 4

∣ u ∣ = 3

3 ∣ 2 x + 5 ∣ = 15

What is the answer to x^2-4|x-1|+5x+3=0 ?
The answer to x^2-4|x-1|+5x+3=0 is x=(-9-sqrt(85))/2 \lor x=(-9+sqrt(85))/2
Solve for x: x^2-4|x-1|+5x+3=0
The solution is x=(-9-sqrt(85))/2 \lor x=(-9+sqrt(85))/2