What is the answer to 3x^2-7|x|+4=0 ?

The answer to 3x^2-7|x|+4=0 is x=-4/3 \lor x=-1\lor x=1\lor x= 4/3

Solve for x: 3x^2-7|x|+4=0

The solution is x=-4/3 \lor x=-1\lor x=1\lor x= 4/3

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3 x^{2} - 7 ∣ x ∣ + 4 = 0

x = - \frac{4}{3} or x = - 1 or x = 1 or x = \frac{4}{3}

Decimal Notation

x = - 1.33333 \dots, x = - 1, x = 1, x = 1.33333 \dots

Solution steps

3 x^{2} - 7 ∣ x ∣ + 4 = 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

(x = - \frac{4}{3} or x = - 1) or (x = 1 or x = \frac{4}{3})

x = - \frac{4}{3} or x = - 1 or x = 1 or x = \frac{4}{3}

x, ∣ x ∣ + y = 2

- 1 - 2 ∣ 5 - 3 x ∣ = x

∣ 3 u + 6 ∣ = 42

∣ 2 x - 3 ∣ = \frac{x}{5}

- ∣ 12 - 2 x ∣ = - 7

What is the answer to 3x^2-7|x|+4=0 ?
The answer to 3x^2-7|x|+4=0 is x=-4/3 \lor x=-1\lor x=1\lor x= 4/3
Solve for x: 3x^2-7|x|+4=0
The solution is x=-4/3 \lor x=-1\lor x=1\lor x= 4/3