What is the answer to |x^2-4x|=4 ?

The answer to |x^2-4x|=4 is x=2(1-sqrt(2))\lor x=2\lor x=2(1+sqrt(2))

Solve for x: |x^2-4x|=4

The solution is x=2(1-sqrt(2))\lor x=2\lor x=2(1+sqrt(2))

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x^{2} - 4 x = 4

x = 2 (1 - 2) or x = 2 or x = 2 (1 + 2)

Decimal Notation

x = - 0.82842 \dots, x = 2, x = 4.82842 \dots

Solution steps

x^{2} - 4 x = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x = - 4 or x^{2} - 4 x = 4

x^{2} - 4 x = - 4 or x^{2} - 4 x = 4

x = 2 or (x = 2 (1 - 2) or x = 2 (1 + 2))

x = 2 (1 - 2) or x = 2 or x = 2 (1 + 2)

∣ 2 z - 3 ∣ = 0

∣ 3 - z ∣ = 9

9 - 4 ∣ x + 10 ∣ = - 15

∣ 5 x - 4 ∣ = 7

\frac{3 - x}{3} - 2 = 0

What is the answer to |x^2-4x|=4 ?
The answer to |x^2-4x|=4 is x=2(1-sqrt(2))\lor x=2\lor x=2(1+sqrt(2))
Solve for x: |x^2-4x|=4
The solution is x=2(1-sqrt(2))\lor x=2\lor x=2(1+sqrt(2))