What are the solutions to the equation (p+8)(p+6)+5=0 ?

The solutions to the equation (p+8)(p+6)+5=0 are p=-7+2i,p=-7-2i

Find the zeros of (p+8)(p+6)+5=0

The zeros of (p+8)(p+6)+5=0 are p=-7+2i,p=-7-2i

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(p + 8) (p + 6) + 5 = 0

p = - 7 + 2 i, p = - 7 - 2 i

Solution steps

(p + 8) (p + 6) + 5 = 0

Expand

(p + 8) (p + 6) + 5 : p^{2} + 14 p + 53

p^{2} + 14 p + 53 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 53}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 53 : 4 i

p_{1, 2} = \frac{- 14 \pm 4 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 14 + 4 i}{2 \cdot 1}, p_{2} = \frac{- 14 - 4 i}{2 \cdot 1}

p = \frac{- 14 + 4 i}{2 \cdot 1} : - 7 + 2 i

p = \frac{- 14 - 4 i}{2 \cdot 1} : - 7 - 2 i

The solutions to the quadratic equation are:

p = - 7 + 2 i, p = - 7 - 2 i

2.5 x + 3 = 35.5

15 - 2 x - x^{2}

80 - \frac{4000}{50}

s - 1 \geq 5.81

6 x^{2} - 19 x + 10

What are the solutions to the equation (p+8)(p+6)+5=0 ?
The solutions to the equation (p+8)(p+6)+5=0 are p=-7+2i,p=-7-2i
Find the zeros of (p+8)(p+6)+5=0
The zeros of (p+8)(p+6)+5=0 are p=-7+2i,p=-7-2i