What are the solutions to the equation 7x^2-14x+2=0 ?

The solutions to the equation 7x^2-14x+2=0 are x=(7+sqrt(35))/7 ,x=(7-sqrt(35))/7

Find the zeros of 7x^2-14x+2=0

The zeros of 7x^2-14x+2=0 are x=(7+sqrt(35))/7 ,x=(7-sqrt(35))/7

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7 x^{2} - 14 x + 2 = 0

x = \frac{7 + 35}{7}, x = \frac{7 - 35}{7}

Decimal Notation

x = 1.84515 \dots, x = 0.15484 \dots

Solution steps

7 x^{2} - 14 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 \cdot 2 = 235

x_{1, 2} = \frac{- ( - 14 ) \pm 2 35}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 35}{2 \cdot 7}, x_{2} = \frac{- ( - 14 ) - 2 35}{2 \cdot 7}

x = \frac{- ( - 14 ) + 2 35}{2 \cdot 7} : \frac{7 + 35}{7}

x = \frac{- ( - 14 ) - 2 35}{2 \cdot 7} : \frac{7 - 35}{7}

The solutions to the quadratic equation are:

x = \frac{7 + 35}{7}, x = \frac{7 - 35}{7}

9 + \frac{n}{4} = 15

a^{2} b - b^{3}

2 y (9 x^{3} y)

x^{2} + (x^{2} + 6^{2}) = 356

7 x^{5} \cdot 42 x y^{9}

What are the solutions to the equation 7x^2-14x+2=0 ?
The solutions to the equation 7x^2-14x+2=0 are x=(7+sqrt(35))/7 ,x=(7-sqrt(35))/7
Find the zeros of 7x^2-14x+2=0
The zeros of 7x^2-14x+2=0 are x=(7+sqrt(35))/7 ,x=(7-sqrt(35))/7