What is the answer to |x^2+2x-5|=3 ?

The answer to |x^2+2x-5|=3 is x=-4\lor x=-1-sqrt(3)\lor x=-1+sqrt(3)\lor x=2

Solve for x: |x^2+2x-5|=3

The solution is x=-4\lor x=-1-sqrt(3)\lor x=-1+sqrt(3)\lor x=2

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x^{2} + 2 x - 5 = 3

x = - 4 or x = - 1 - 3 or x = - 1 + 3 or x = 2

Decimal

x = - 4, x = - 2.73205 \dots, x = 0.73205 \dots, x = 2

Solution steps

x^{2} + 2 x - 5 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 2 x - 5 = - 3 or x^{2} + 2 x - 5 = 3

x^{2} + 2 x - 5 = - 3 or x^{2} + 2 x - 5 = 3

(x = - 1 - 3 or x = - 1 + 3) or (x = - 4 or x = 2)

x = - 4 or x = - 1 - 3 or x = - 1 + 3 or x = 2

- 2 ∣ 5 x - 7 ∣ + 9 = - 7

∣ 4 x + 2 ∣ = 5 x - 1

3 - 2 ∣ 4 x - 1 ∣ = 9

4 ∣ 4 + 10 b ∣ = 24

4 - 2 ∣ 3 - 2 x ∣ = - 2

What is the answer to |x^2+2x-5|=3 ?
The answer to |x^2+2x-5|=3 is x=-4\lor x=-1-sqrt(3)\lor x=-1+sqrt(3)\lor x=2
Solve for x: |x^2+2x-5|=3
The solution is x=-4\lor x=-1-sqrt(3)\lor x=-1+sqrt(3)\lor x=2