What is the answer to x^2+7x-1=|x+2|+9 ?

The answer to x^2+7x-1=|x+2|+9 is x=-2(2+sqrt(6))\lor x=-3+sqrt(21)

Solve for x: x^2+7x-1=|x+2|+9

The solution is x=-2(2+sqrt(6))\lor x=-3+sqrt(21)

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x^{2} + 7 x - 1 = ∣ x + 2 ∣ + 9

x = - 2 (2 + 6) or x = - 3 + 21

Decimal Notation

x = - 8.89897 \dots, x = 1.58257 \dots

Solution steps

x^{2} + 7 x - 1 = ∣ x + 2 ∣ + 9

Find positive and negative intervals

x < - 2, x \geq - 2

Solve the inequality for each interval

x = - 2 (2 + 6) or x = - 3 + 21

∣ 16 x + 12 ∣ = 8

∣ 6 - 2 x ∣ + 7 = 12 x + 7

∣ x + 3 ∣ = 6

∣ x + 6 ∣ + 3 = 16

∣ g + 7 ∣ + 13 = 4

What is the answer to x^2+7x-1=|x+2|+9 ?
The answer to x^2+7x-1=|x+2|+9 is x=-2(2+sqrt(6))\lor x=-3+sqrt(21)
Solve for x: x^2+7x-1=|x+2|+9
The solution is x=-2(2+sqrt(6))\lor x=-3+sqrt(21)