What is factor 2x^3-7x^2+4x+4 ?

The solution to factor 2x^3-7x^2+4x+4 is (2x+1)(x-2)^2

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factor 2x^3-7x^2+4x+4

factor

2 x^{3} - 7 x^{2} + 4 x + 4

(2 x + 1) (x - 2)^{2}

Solution steps

2 x^{3} - 7 x^{2} + 4 x + 4

Use the rational root theorem

= (2 x + 1) \frac{2 x ^{3} - 7 x ^{2} + 4 x + 4}{2 x + 1}

\frac{2 x ^{3} - 7 x ^{2} + 4 x + 4}{2 x + 1} = x^{2} - 4 x + 4

= (2 x + 1) (x^{2} - 4 x + 4)

Factor

x^{2} - 4 x + 4 : (x - 2) (x - 2)

= (2 x + 1) (x - 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (2 x + 1) (x - 2)^{2}

- \frac{1}{3} \cdot 21

(6^{\frac{1}{2}} \cdot 4^{\frac{1}{3}})^{2}

12 x^{2} y - 3 y

83 = \frac{1}{2} \cdot (\frac{π}{4}) r^{2}

(- 9 + 2 i) - (- 12 + 4 i)

What is factor 2x^3-7x^2+4x+4 ?
The solution to factor 2x^3-7x^2+4x+4 is (2x+1)(x-2)^2