What is the answer to |x^2+7x-4|=4 ?

The answer to |x^2+7x-4|=4 is x=-8\lor x=-7\lor x=0\lor x=1

Solve for x: |x^2+7x-4|=4

The solution is x=-8\lor x=-7\lor x=0\lor x=1

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x^{2} + 7 x - 4 = 4

x = - 8 or x = - 7 or x = 0 or x = 1

Solution steps

x^{2} + 7 x - 4 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 7 x - 4 = - 4 or x^{2} + 7 x - 4 = 4

x^{2} + 7 x - 4 = - 4 or x^{2} + 7 x - 4 = 4

(x = - 7 or x = 0) or (x = - 8 or x = 1)

x = - 8 or x = - 7 or x = 0 or x = 1

∣ 3 x - 6 ∣ = 10

- 0.3 ∣ 3 + 8 x ∣ = 0.9

∣ 5 x ∣ = 6 - x

∣ 2 a x - b ∣ = 3 b

∣ 7 x + 3 ∣ = x

What is the answer to |x^2+7x-4|=4 ?
The answer to |x^2+7x-4|=4 is x=-8\lor x=-7\lor x=0\lor x=1
Solve for x: |x^2+7x-4|=4
The solution is x=-8\lor x=-7\lor x=0\lor x=1