What is the answer to |x^2-4x-5|=5 ?

The answer to |x^2-4x-5|=5 is x=2-sqrt(14)\lor x=0\lor x=4\lor x=2+sqrt(14)

Solve for x: |x^2-4x-5|=5

The solution is x=2-sqrt(14)\lor x=0\lor x=4\lor x=2+sqrt(14)

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x^{2} - 4 x - 5 = 5

x = 2 - 14 or x = 0 or x = 4 or x = 2 + 14

Decimal Notation

x = - 1.74165 \dots, x = 0, x = 4, x = 5.74165 \dots

Solution steps

x^{2} - 4 x - 5 = 5

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x - 5 = - 5 or x^{2} - 4 x - 5 = 5

x^{2} - 4 x - 5 = - 5 or x^{2} - 4 x - 5 = 5

(x = 0 or x = 4) or (x = 2 - 14 or x = 2 + 14)

x = 2 - 14 or x = 0 or x = 4 or x = 2 + 14

- 4 ∣ 5 - 2 n ∣ = - 12

3 ∣ 2 x - 5 ∣ - 4 = - 1

∣ - 3 n - 4 ∣ = 17

10 - 2 ∣ x - 3 ∣ = 3

∣ x - 92.95 ∣ = 1.55

What is the answer to |x^2-4x-5|=5 ?
The answer to |x^2-4x-5|=5 is x=2-sqrt(14)\lor x=0\lor x=4\lor x=2+sqrt(14)
Solve for x: |x^2-4x-5|=5
The solution is x=2-sqrt(14)\lor x=0\lor x=4\lor x=2+sqrt(14)