What are the solutions to the equation -x^2+8x-7=0 ?

The solutions to the equation -x^2+8x-7=0 are x=1,x=7

Find the zeros of -x^2+8x-7=0

The zeros of -x^2+8x-7=0 are x=1,x=7

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- x^{2} + 8 x - 7 = 0

x = 1, x = 7

Solution steps

- x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 7) = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 ( - 1 )}, x_{2} = \frac{- 8 - 6}{2 ( - 1 )}

x = \frac{- 8 + 6}{2 ( - 1 )} : 1

x = \frac{- 8 - 6}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = 1, x = 7

- \frac{1}{3} + \frac{3}{8}

8 \geq y \geq 0

w^{3 x} + 8

x^{- \frac{1}{2}} \cdot x^{2}

\frac{3}{4} y^{2} - 11 = 232

What are the solutions to the equation -x^2+8x-7=0 ?
The solutions to the equation -x^2+8x-7=0 are x=1,x=7
Find the zeros of -x^2+8x-7=0
The zeros of -x^2+8x-7=0 are x=1,x=7