What is the answer to |x^2+6x|=9 ?

The answer to |x^2+6x|=9 is x=-3(1+sqrt(2))\lor x=-3\lor x=3(sqrt(2)-1)

Solve for x: |x^2+6x|=9

The solution is x=-3(1+sqrt(2))\lor x=-3\lor x=3(sqrt(2)-1)

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x^{2} + 6 x = 9

x = - 3 (1 + 2) or x = - 3 or x = 3 (2 - 1)

Decimal Notation

x = - 7.24264 \dots, x = - 3, x = 1.24264 \dots

Solution steps

x^{2} + 6 x = 9

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 6 x = - 9 or x^{2} + 6 x = 9

x^{2} + 6 x = - 9 or x^{2} + 6 x = 9

x = - 3 or (x = - 3 (1 + 2) or x = 3 (2 - 1))

x = - 3 (1 + 2) or x = - 3 or x = 3 (2 - 1)

∣ x - 1 ∣ - 1 = 3

∣ 3 x ∣ = - 12

3 - ∣ x + 2 ∣ = 1

x, ∣ 2 x - 1 ∣ = 5

∣ 9 x - 49 ∣ = - 41

What is the answer to |x^2+6x|=9 ?
The answer to |x^2+6x|=9 is x=-3(1+sqrt(2))\lor x=-3\lor x=3(sqrt(2)-1)
Solve for x: |x^2+6x|=9
The solution is x=-3(1+sqrt(2))\lor x=-3\lor x=3(sqrt(2)-1)