What is the answer to (x-2)^2+|x-2|-2=0 ?

The answer to (x-2)^2+|x-2|-2=0 is x=1\lor x=3

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(x-2)^2+|x-2|-2=0

(x - 2)^{2} + ∣ x - 2 ∣ - 2 = 0

x = 1 or x = 3

Solution steps

(x - 2)^{2} + ∣ x - 2 ∣ - 2 = 0

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

x = 1 or x = 3

- 2 ∣ x + 3 ∣ - 4 = - 8

∣ - x + 3 ∣ = 8

∣ 6 x + 1 ∣ = - 7

- 8 ∣ 10 n - 5 ∣ = - 120

∣ x + 3 ∣ = - 5

What is the answer to (x-2)^2+|x-2|-2=0 ?
The answer to (x-2)^2+|x-2|-2=0 is x=1\lor x=3
Solve for x: (x-2)^2+|x-2|-2=0
The solution is x=1\lor x=3