What is the answer to x^2+6-8=|x+4|+4 ?

The answer to x^2+6-8=|x+4|+4 is x=(1-sqrt(41))/2 \lor x=(1+sqrt(41))/2

Solve for x: x^2+6-8=|x+4|+4

The solution is x=(1-sqrt(41))/2 \lor x=(1+sqrt(41))/2

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x^{2} + 6 - 8 = ∣ x + 4 ∣ + 4

x = \frac{1 - 41}{2} or x = \frac{1 + 41}{2}

Decimal Notation

x = - 2.70156 \dots, x = 3.70156 \dots

Solution steps

x^{2} + 6 - 8 = ∣ x + 4 ∣ + 4

Find positive and negative intervals

x < - 4, x \geq - 4

Solve the inequality for each interval

No Solution or (x = \frac{1 - 41}{2} or x = \frac{1 + 41}{2})

x = \frac{1 - 41}{2} or x = \frac{1 + 41}{2}

∣ x + 8 ∣ + 4 = 0

0.5 ∣ 8.8 - 1.6 x ∣ = 2

2 ∣ 3 a - 6 ∣ = 24

\frac{1}{2} ∣ x + 4 ∣ = 5

∣ 2 x - 6 ∣ = 12

What is the answer to x^2+6-8=|x+4|+4 ?
The answer to x^2+6-8=|x+4|+4 is x=(1-sqrt(41))/2 \lor x=(1+sqrt(41))/2
Solve for x: x^2+6-8=|x+4|+4
The solution is x=(1-sqrt(41))/2 \lor x=(1+sqrt(41))/2