What is the answer to |2x^2-3|=2x ?

The answer to |2x^2-3|=2x is x=(sqrt(7)-1)/2 \lor x=(1+sqrt(7))/2

Solve for x: |2x^2-3|=2x

The solution is x=(sqrt(7)-1)/2 \lor x=(1+sqrt(7))/2

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2 x^{2} - 3 = 2 x

x = \frac{7 - 1}{2} or x = \frac{1 + 7}{2}

Decimal Notation

x = 0.82287 \dots, x = 1.82287 \dots

Solution steps

2 x^{2} - 3 = 2 x

Find positive and negative intervals

x \leq - \frac{3}{2}, - \frac{3}{2} < x < \frac{3}{2}, x \geq \frac{3}{2}

Solve the inequality for each interval

No Solution or x = \frac{7 - 1}{2} or x = \frac{1 + 7}{2}

x = \frac{7 - 1}{2} or x = \frac{1 + 7}{2}

∣ x ∣ - 1 = 7

∣ 1 - 3 x ∣ = x + 5

∣ 3 x - 5 ∣ = x^{2} - x - 2

∣ 4 x - 5 ∣ = 21

x^{2} + 5 ∣ x ∣ + 6 = 0

What is the answer to |2x^2-3|=2x ?
The answer to |2x^2-3|=2x is x=(sqrt(7)-1)/2 \lor x=(1+sqrt(7))/2
Solve for x: |2x^2-3|=2x
The solution is x=(sqrt(7)-1)/2 \lor x=(1+sqrt(7))/2