What are the solutions to the equation -x^2-18x-54=0 ?

The solutions to the equation -x^2-18x-54=0 are x=-3(3+sqrt(3)),x=-3(3-sqrt(3))

Find the zeros of -x^2-18x-54=0

The zeros of -x^2-18x-54=0 are x=-3(3+sqrt(3)),x=-3(3-sqrt(3))

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- x^{2} - 18 x - 54 = 0

x = - 3 (3 + 3), x = - 3 (3 - 3)

Decimal Notation

x = - 14.19615 \dots, x = - 3.80384 \dots

Solution steps

- x^{2} - 18 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 1 ) ( - 54 )}{2 ( - 1 )}

(- 18)^{2} - 4 (- 1) (- 54) = 63

x_{1, 2} = \frac{- ( - 18 ) \pm 6 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 18 ) - 6 3}{2 ( - 1 )}

x = \frac{- ( - 18 ) + 6 3}{2 ( - 1 )} : - 3 (3 + 3)

x = \frac{- ( - 18 ) - 6 3}{2 ( - 1 )} : - 3 (3 - 3)

The solutions to the quadratic equation are:

x = - 3 (3 + 3), x = - 3 (3 - 3)

318 - 22

∣ 2 x - 2 ∣ < 8

x + \frac{x + 5}{8} = \frac{x + 5}{16}

lo g_{9} (4 z + 10 t)

2 x + 31 = 7 x - 24

What are the solutions to the equation -x^2-18x-54=0 ?
The solutions to the equation -x^2-18x-54=0 are x=-3(3+sqrt(3)),x=-3(3-sqrt(3))
Find the zeros of -x^2-18x-54=0
The zeros of -x^2-18x-54=0 are x=-3(3+sqrt(3)),x=-3(3-sqrt(3))