What is the answer to |x^2-5x+1|=3 ?

The answer to |x^2-5x+1|=3 is x=(5-sqrt(33))/2 \lor x=1\lor x=4\lor x=(5+sqrt(33))/2

Solve for x: |x^2-5x+1|=3

The solution is x=(5-sqrt(33))/2 \lor x=1\lor x=4\lor x=(5+sqrt(33))/2

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x^{2} - 5 x + 1 = 3

x = \frac{5 - 33}{2} or x = 1 or x = 4 or x = \frac{5 + 33}{2}

Decimal Notation

x = - 0.37228 \dots, x = 1, x = 4, x = 5.37228 \dots

Solution steps

x^{2} - 5 x + 1 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 5 x + 1 = - 3 or x^{2} - 5 x + 1 = 3

x^{2} - 5 x + 1 = - 3 or x^{2} - 5 x + 1 = 3

(x = 1 or x = 4) or (x = \frac{5 - 33}{2} or x = \frac{5 + 33}{2})

x = \frac{5 - 33}{2} or x = 1 or x = 4 or x = \frac{5 + 33}{2}

3 ∣ b + 2 ∣ - 9 = - 5

∣ - 5 y + 7 ∣ + 8 = 4

x^{13} = ∣ 2 x - 3 ∣

3 x^{1} = 4

∣ 3 u + 12 ∣ = 3

What is the answer to |x^2-5x+1|=3 ?
The answer to |x^2-5x+1|=3 is x=(5-sqrt(33))/2 \lor x=1\lor x=4\lor x=(5+sqrt(33))/2
Solve for x: |x^2-5x+1|=3
The solution is x=(5-sqrt(33))/2 \lor x=1\lor x=4\lor x=(5+sqrt(33))/2